Lando Norris, the reigning Formula One world champion, signed a contract extension with McLaren on August 29, 2026, keeping him at the team until at least the end of 2030 [1, 2, 3, 4, 5, 6]. The contract also includes a multi-year option to extend beyond 2030 [2, 4, 5, 6].
Norris made his McLaren F1 debut in 2019 after joining their junior program in 2017 [1, 2, 3, 4, 5, 6]. At 26 years old, he has won 13 grands prix and scored 18 poles with McLaren, becoming the team’s longest-serving driver with 163 races [2, 3, 4, 5]. McLaren won consecutive constructors' championships in 2024 and 2025, with Norris capturing the drivers' title in 2025 [1, 3, 6].
Norris announced the extension at a McLaren friends and family day at the team’s Woking factory, where he was gifted an MCL39 car from McLaren’s 2025 title-winning season [2, 3, 4, 5]. He said, "At the minute there's really no reason to want to even put a thought into somewhere else. I kind of want my whole career to be with McLaren because I'm happy here and I don't want to change" [2]. He described signing the new deal as "the easiest decision I've had to make in my career so far" and said he is "very, very happy at the end of my career to say that McLaren is the only team I've been with" [3].
Despite media speculation about his pay, Norris denied that his salary is as high as the reported €60 million per year, calling those figures exaggerated [2, 4, 5]. McLaren team principal Andrea Stella said the extension "gives us important continuity and reinforces our confidence in the direction we are taking together. With him and Oscar [Piastri], we know we can count not only on one of the strongest partnerships but also on one of the most united and close-knit teams in Formula One" [2].
The 2026 season has been challenging for McLaren as they adapted to new regulations, but Norris won the last two races in Hungary and the Netherlands this month [1, 2, 3, 6]. He currently ranks fourth in the 2026 drivers' championship, trailing the leader by 83 points with 11 races remaining [6].
